What are the solutions to the equation -4x^2+9x-1=0 ?

The solutions to the equation -4x^2+9x-1=0 are x=(9-sqrt(65))/8 ,x=(9+sqrt(65))/8

Find the zeros of -4x^2+9x-1=0

The zeros of -4x^2+9x-1=0 are x=(9-sqrt(65))/8 ,x=(9+sqrt(65))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 9 x - 1 = 0

x = \frac{9 - 65}{8}, x = \frac{9 + 65}{8}

Decimal Notation

x = 0.11721 \dots, x = 2.13278 \dots

Solution steps

- 4 x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 4 ) ( - 1 )}{2 ( - 4 )}

9^{2} - 4 (- 4) (- 1) = 65

x_{1, 2} = \frac{- 9 \pm 65}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 9 + 65}{2 ( - 4 )}, x_{2} = \frac{- 9 - 65}{2 ( - 4 )}

x = \frac{- 9 + 65}{2 ( - 4 )} : \frac{9 - 65}{8}

x = \frac{- 9 - 65}{2 ( - 4 )} : \frac{9 + 65}{8}

The solutions to the quadratic equation are:

x = \frac{9 - 65}{8}, x = \frac{9 + 65}{8}

∣ 2 x + 6 ∣ \leq 24

lo g_{3} (x - 1) + lo g_{3} (2 - 3 x) > 2

0 = 3 t^{2} - 24 t + 36

- 2 (3 w + 6) - (4 w - 3) = 21

\frac{2}{n + 8} + \frac{4}{n + 1}

What are the solutions to the equation -4x^2+9x-1=0 ?
The solutions to the equation -4x^2+9x-1=0 are x=(9-sqrt(65))/8 ,x=(9+sqrt(65))/8
Find the zeros of -4x^2+9x-1=0
The zeros of -4x^2+9x-1=0 are x=(9-sqrt(65))/8 ,x=(9+sqrt(65))/8