What are the solutions to the equation x^2-11x-18=0 ?

The solutions to the equation x^2-11x-18=0 are x=(11+sqrt(193))/2 ,x=(11-sqrt(193))/2

Find the zeros of x^2-11x-18=0

The zeros of x^2-11x-18=0 are x=(11+sqrt(193))/2 ,x=(11-sqrt(193))/2

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x^{2} - 11 x - 18 = 0

x = \frac{11 + 193}{2}, x = \frac{11 - 193}{2}

Decimal Notation

x = 12.44622 \dots, x = - 1.44622 \dots

Solution steps

x^{2} - 11 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 18) = 193

x_{1, 2} = \frac{- ( - 11 ) \pm 193}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 193}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 193}{2 \cdot 1}

x = \frac{- ( - 11 ) + 193}{2 \cdot 1} : \frac{11 + 193}{2}

x = \frac{- ( - 11 ) - 193}{2 \cdot 1} : \frac{11 - 193}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 193}{2}, x = \frac{11 - 193}{2}

\frac{- 15 r ^{6} s ^{7} t ^{4}}{3 r ^{2} s ^{9} t ^{7}}

5 x^{2} + 3 x \geq 3 x^{2} + 20

x^{4} - y^{6}

- 5 t^{2} + 50 t + 5

lo g_{4} (\frac{1}{16}) = x

What are the solutions to the equation x^2-11x-18=0 ?
The solutions to the equation x^2-11x-18=0 are x=(11+sqrt(193))/2 ,x=(11-sqrt(193))/2
Find the zeros of x^2-11x-18=0
The zeros of x^2-11x-18=0 are x=(11+sqrt(193))/2 ,x=(11-sqrt(193))/2