What is factor 2(a+b)^2+7(a+b)-4 ?

The solution to factor 2(a+b)^2+7(a+b)-4 is (2(a+b)-1)(a+b+4)

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factor 2(a+b)^2+7(a+b)-4

factor

2 (a + b)^{2} + 7 (a + b) - 4

(2 (a + b) - 1) (a + b + 4)

Solution steps

2 (a + b)^{2} + 7 (a + b) - 4

Break the expression into groups

= (2 (a + b)^{2} - (a + b)) + (8 (a + b) - 4)

Factor out

(a + b)

from

2 (a + b)^{2} - (a + b) : (a + b) (2 (a + b) - 1)

Factor out

4

from

8 (a + b) - 4 : 4 (2 (a + b) - 1)

= (a + b) (2 (a + b) - 1) + 4 (2 (a + b) - 1)

Factor out common term

2 (a + b) - 1

= (2 (a + b) - 1) ((a + b) + 4)

Refine

= (a + b + 4) (2 (a + b) - 1)

144 - 73 x + 4 x^{2} = 0

5 x^{2} + 10 x - 40

5 x^{2} - 10 x + 4 = 0

7 a - 14 a^{2} = 0

\frac{( n ( n + 1 ) ( 2 n + 1 ) )}{6} + (n + 1)^{2}

What is factor 2(a+b)^2+7(a+b)-4 ?
The solution to factor 2(a+b)^2+7(a+b)-4 is (2(a+b)-1)(a+b+4)