What is -4z+31>= 17z+23-4z+31>= 17z+23 ?

The solution to -4z+31>= 17z+23-4z+31>= 17z+23 is z<=-23/17

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-4z+31>= 17z+23-4z+31>= 17z+23

- 4 z + 31 \geq 17 z + 23 - 4 z + 31 \geq 17 z + 23

z \leq - \frac{23}{17}

Interval Notation

(- \infty, - \frac{23}{17}]

Decimal Notation

z \leq - 1.35294 \dots

Solution steps

- 4 z + 31 \geq 17 z + 23 - 4 z + 31 \geq 17 z + 23

a \geq u \geq b

then

a \geq u and u \geq b

- 4 z + 31 \geq 17 z + 23 - 4 z + 31 and 17 z + 23 - 4 z + 31 \geq 17 z + 23

- 4 z + 31 \geq 17 z + 23 - 4 z + 31 : z \leq - \frac{23}{17}

17 z + 23 - 4 z + 31 \geq 17 z + 23 : z \leq \frac{31}{4}

Combine the intervals

z \leq - \frac{23}{17} and z \leq \frac{31}{4}

Merge Overlapping Intervals

z \leq - \frac{23}{17}

4 (1 - 3 i)^{3}

7 \cdot 15

6 - 5 x \leq 10

∣ - 8 a - 3 ∣ > 11

8 x^{2} - 6 x - 5 = 0

What is -4z+31>= 17z+23-4z+31>= 17z+23 ?
The solution to -4z+31>= 17z+23-4z+31>= 17z+23 is z<=-23/17