What are the solutions to the equation 8x^2-6x-5=0 ?

The solutions to the equation 8x^2-6x-5=0 are x= 5/4 ,x=-1/2

Find the zeros of 8x^2-6x-5=0

The zeros of 8x^2-6x-5=0 are x= 5/4 ,x=-1/2

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8 x^{2} - 6 x - 5 = 0

x = \frac{5}{4}, x = - \frac{1}{2}

Decimal Notation

x = 1.25, x = - 0.5

Solution steps

8 x^{2} - 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 8 ( - 5 )}{2 \cdot 8}

(- 6)^{2} - 4 \cdot 8 (- 5) = 14

x_{1, 2} = \frac{- ( - 6 ) \pm 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 14}{2 \cdot 8}, x_{2} = \frac{- ( - 6 ) - 14}{2 \cdot 8}

x = \frac{- ( - 6 ) + 14}{2 \cdot 8} : \frac{5}{4}

x = \frac{- ( - 6 ) - 14}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{1}{2}

\frac{7}{8} - \frac{1}{4}

(\frac{1}{6})^{6}

(j + 5)^{2} = 20

m^{4} - n^{4}

2 a x - 6 b x + a y - 3 b y

What are the solutions to the equation 8x^2-6x-5=0 ?
The solutions to the equation 8x^2-6x-5=0 are x= 5/4 ,x=-1/2
Find the zeros of 8x^2-6x-5=0
The zeros of 8x^2-6x-5=0 are x= 5/4 ,x=-1/2