What are the solutions to the equation (j+5)^2=20 ?

The solutions to the equation (j+5)^2=20 are j=2sqrt(5)-5,j=-2sqrt(5)-5

Find the zeros of (j+5)^2=20

The zeros of (j+5)^2=20 are j=2sqrt(5)-5,j=-2sqrt(5)-5

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(j + 5)^{2} = 20

j = 25 - 5, j = - 25 - 5

Decimal Notation

j = - 0.52786 \dots, j = - 9.47213 \dots

Solution steps

(j + 5)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

j + 5 = 20 : j = 25 - 5

Solve

j + 5 = - 20 : j = - 25 - 5

The solutions to the quadratic equation are:

j = 25 - 5, j = - 25 - 5

m^{4} - n^{4}

2 a x - 6 b x + a y - 3 b y

- 8 + 4 i

2 x + 35 < x^{2}

x^{2} - \frac{1}{4} x - \frac{15}{64} = 0

What are the solutions to the equation (j+5)^2=20 ?
The solutions to the equation (j+5)^2=20 are j=2sqrt(5)-5,j=-2sqrt(5)-5
Find the zeros of (j+5)^2=20
The zeros of (j+5)^2=20 are j=2sqrt(5)-5,j=-2sqrt(5)-5