en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x+35<x^2

Solution

2 x + 35 < x^{2}

Solution

x < - 5 or x > 7

+1

Interval Notation

(- \infty, - 5) \cup (7, \infty)

Solution steps

2 x + 35 < x^{2}

Rewrite in standard form

2 x + 35 - x^{2} < 0

Factor

2 x + 35 - x^{2} : - (x + 5) (x - 7)

- (x + 5) (x - 7) < 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x + 5) (x - 7)) (- 1) > 0 \cdot (- 1)

Simplify

(x + 5) (x - 7) > 0

Identify the intervals

x < - 5 or x > 7

Popular Examples

x^2-1/4 x-15/64 =0

x^{2} - \frac{1}{4} x - \frac{15}{64} = 0

2 x^{2} + 10 x + 8 = 0

factor 4x-x^2-3 factor

4 x - x^{2} - 3

simplify k^{-1/6}simplify

k^{- \frac{1}{6}}

simplify (m^6n^3)/(m^2n^6)simplify

\frac{m ^{6} n ^{3}}{m ^{2} n ^{6}}

Frequently Asked Questions (FAQ)

What is 2x+35<x^2 ?
The solution to 2x+35<x^2 is x<-5\lor x>7