What are the solutions to the equation x^2-15x=-56 ?

The solutions to the equation x^2-15x=-56 are x=8,x=7

Find the zeros of x^2-15x=-56

The zeros of x^2-15x=-56 are x=8,x=7

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x^{2} - 15 x = - 56

x = 8, x = 7

Solution steps

x^{2} - 15 x = - 56

Move

56

to the left side

x^{2} - 15 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 56 = 1

x_{1, 2} = \frac{- ( - 15 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 1}{2 \cdot 1}

x = \frac{- ( - 15 ) + 1}{2 \cdot 1} : 8

x = \frac{- ( - 15 ) - 1}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 8, x = 7

8 (\frac{3}{4})

- 4 (v + 2) + 2 = 2 (v + 6)

5 a + 5

1 + \frac{6}{x + 1} \leq \frac{6}{x}

a^{10} - 28 a^{5} + 27

What are the solutions to the equation x^2-15x=-56 ?
The solutions to the equation x^2-15x=-56 are x=8,x=7
Find the zeros of x^2-15x=-56
The zeros of x^2-15x=-56 are x=8,x=7