What are the solutions to the equation 9p^2-18p-67=5 ?

The solutions to the equation 9p^2-18p-67=5 are p=4,p=-2

Find the zeros of 9p^2-18p-67=5

The zeros of 9p^2-18p-67=5 are p=4,p=-2

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9 p^{2} - 18 p - 67 = 5

p = 4, p = - 2

Solution steps

9 p^{2} - 18 p - 67 = 5

Move

5

to the left side

9 p^{2} - 18 p - 72 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 ( - 72 )}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 (- 72) = 54

p_{1, 2} = \frac{- ( - 18 ) \pm 54}{2 \cdot 9}

Separate the solutions

p_{1} = \frac{- ( - 18 ) + 54}{2 \cdot 9}, p_{2} = \frac{- ( - 18 ) - 54}{2 \cdot 9}

p = \frac{- ( - 18 ) + 54}{2 \cdot 9} : 4

p = \frac{- ( - 18 ) - 54}{2 \cdot 9} : - 2

The solutions to the quadratic equation are:

p = 4, p = - 2

- 15 \cdot - 15

- 7 (- x + 4) = - 20 - x

\frac{( 3 \cdot 2 ^{n} ) \cdot ( 3 \cdot 8 ^{n} )}{3 \cdot 1 6 ^{1 - n}}

\frac{\frac{1}{1 + x + h} - \frac{1}{1 + x}}{h}

9 X + 7 = 52

What are the solutions to the equation 9p^2-18p-67=5 ?
The solutions to the equation 9p^2-18p-67=5 are p=4,p=-2
Find the zeros of 9p^2-18p-67=5
The zeros of 9p^2-18p-67=5 are p=4,p=-2