What are the solutions to the equation 0=x^2-4x-21 ?

The solutions to the equation 0=x^2-4x-21 are x=7,x=-3

Find the zeros of 0=x^2-4x-21

The zeros of 0=x^2-4x-21 are x=7,x=-3

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0 = x^{2} - 4 x - 21

x = 7, x = - 3

Solution steps

0 = x^{2} - 4 x - 21

Switch sides

x^{2} - 4 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 21) = 10

x_{1, 2} = \frac{- ( - 4 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10}{2 \cdot 1} : 7

x = \frac{- ( - 4 ) - 10}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 7, x = - 3

- \frac{32}{400} x^{2} + x + 3 = 0

6 + \frac{4}{4} + \frac{3}{3}

x^{2} + 25 = 10 x

12 c^{2} + 46 c + 40

What are the solutions to the equation 0=x^2-4x-21 ?
The solutions to the equation 0=x^2-4x-21 are x=7,x=-3
Find the zeros of 0=x^2-4x-21
The zeros of 0=x^2-4x-21 are x=7,x=-3