What are the solutions to the equation -5x^2+50x-135=0 ?

The solutions to the equation -5x^2+50x-135=0 are x=5-sqrt(2)i,x=5+sqrt(2)i

Find the zeros of -5x^2+50x-135=0

The zeros of -5x^2+50x-135=0 are x=5-sqrt(2)i,x=5+sqrt(2)i

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- 5 x^{2} + 50 x - 135 = 0

x = 5 - 2 i, x = 5 + 2 i

Solution steps

- 5 x^{2} + 50 x - 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 5 ) ( - 135 )}{2 ( - 5 )}

Simplify

5 0^{2} - 4 (- 5) (- 135) : 102 i

x_{1, 2} = \frac{- 50 \pm 10 2 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 50 + 10 2 i}{2 ( - 5 )}, x_{2} = \frac{- 50 - 10 2 i}{2 ( - 5 )}

x = \frac{- 50 + 10 2 i}{2 ( - 5 )} : 5 - 2 i

x = \frac{- 50 - 10 2 i}{2 ( - 5 )} : 5 + 2 i

The solutions to the quadratic equation are:

x = 5 - 2 i, x = 5 + 2 i

\frac{( ( x + 1 ) ^{4} - 4 )}{4 ( x + 1 ) ^{2}}^{2}

6^{2} + x^{2} = 1 4^{2}

x^{2} + 125 = 0

x^{2} + 5 x - 50

x^{3} + 4 x^{2} - 11 x - 44

What are the solutions to the equation -5x^2+50x-135=0 ?
The solutions to the equation -5x^2+50x-135=0 are x=5-sqrt(2)i,x=5+sqrt(2)i
Find the zeros of -5x^2+50x-135=0
The zeros of -5x^2+50x-135=0 are x=5-sqrt(2)i,x=5+sqrt(2)i