What are the solutions to the equation -x^2+3x+10=0 ?

The solutions to the equation -x^2+3x+10=0 are x=-2,x=5

Find the zeros of -x^2+3x+10=0

The zeros of -x^2+3x+10=0 are x=-2,x=5

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- x^{2} + 3 x + 10 = 0

x = - 2, x = 5

Solution steps

- x^{2} + 3 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 10}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 10 = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 ( - 1 )}, x_{2} = \frac{- 3 - 7}{2 ( - 1 )}

x = \frac{- 3 + 7}{2 ( - 1 )} : - 2

x = \frac{- 3 - 7}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = - 2, x = 5

a^{2} - 3 a - 4 = 0

∣ y + 1 ∣ < \frac{2}{∣ y ∣}

10000 0^{\frac{3}{5}}

\frac{3}{4} + (\frac{1}{3} \div \frac{1}{6}) - (- \frac{1}{2})

(- \frac{1}{3})^{\frac{4}{5}} \cdot (\frac{1}{3})^{\frac{3}{5}}

What are the solutions to the equation -x^2+3x+10=0 ?
The solutions to the equation -x^2+3x+10=0 are x=-2,x=5
Find the zeros of -x^2+3x+10=0
The zeros of -x^2+3x+10=0 are x=-2,x=5