What are the solutions to the equation x^2=sqrt(12^2-5^2) ?

The solutions to the equation x^2=sqrt(12^2-5^2) are x=sqrt(\sqrt{119)},x=-sqrt(\sqrt{119)}

Find the zeros of x^2=sqrt(12^2-5^2)

The zeros of x^2=sqrt(12^2-5^2) are x=sqrt(\sqrt{119)},x=-sqrt(\sqrt{119)}

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x^{2} = 1 2^{2} - 5^{2}

x = 119, x = - 119

Decimal Notation

x = 3.30283 \dots, x = - 3.30283 \dots

Solution steps

x^{2} = 1 2^{2} - 5^{2}

Simplify

1 2^{2} - 5^{2} : 119

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 119, x = - 119

\frac{r}{3} < - 6

- 7 x^{2} - 2 x + 5

x (x - 4) = 45

v^{2} = 19 v

- 6 - 16 x^{4}

What are the solutions to the equation x^2=sqrt(12^2-5^2) ?
The solutions to the equation x^2=sqrt(12^2-5^2) are x=sqrt(\sqrt{119)},x=-sqrt(\sqrt{119)}
Find the zeros of x^2=sqrt(12^2-5^2)
The zeros of x^2=sqrt(12^2-5^2) are x=sqrt(\sqrt{119)},x=-sqrt(\sqrt{119)}