What are the solutions to the equation x^2+x-210=0 ?

The solutions to the equation x^2+x-210=0 are x=14,x=-15

Find the zeros of x^2+x-210=0

The zeros of x^2+x-210=0 are x=14,x=-15

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x^{2} + x - 210 = 0

x = 14, x = - 15

Solution steps

x^{2} + x - 210 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 210 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 210) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 1}, x_{2} = \frac{- 1 - 29}{2 \cdot 1}

x = \frac{- 1 + 29}{2 \cdot 1} : 14

x = \frac{- 1 - 29}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 14, x = - 15

(x + y) (x + y)

x^{2} + 0.1 x + 0.0025 = 0

x^{3} - x^{2} \geq 3 - 3 x

lo g_{2} (256)

6 a^{4} b^{4} c - 3 a^{3} b^{2} c - 9 a^{2} b^{2}

What are the solutions to the equation x^2+x-210=0 ?
The solutions to the equation x^2+x-210=0 are x=14,x=-15
Find the zeros of x^2+x-210=0
The zeros of x^2+x-210=0 are x=14,x=-15