What are the solutions to the equation x^2-5x-20=0 ?

The solutions to the equation x^2-5x-20=0 are x=(5+sqrt(105))/2 ,x=(5-sqrt(105))/2

Find the zeros of x^2-5x-20=0

The zeros of x^2-5x-20=0 are x=(5+sqrt(105))/2 ,x=(5-sqrt(105))/2

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x^{2} - 5 x - 20 = 0

x = \frac{5 + 105}{2}, x = \frac{5 - 105}{2}

Decimal Notation

x = 7.62347 \dots, x = - 2.62347 \dots

Solution steps

x^{2} - 5 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 20) = 105

x_{1, 2} = \frac{- ( - 5 ) \pm 105}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 105}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 105}{2 \cdot 1}

x = \frac{- ( - 5 ) + 105}{2 \cdot 1} : \frac{5 + 105}{2}

x = \frac{- ( - 5 ) - 105}{2 \cdot 1} : \frac{5 - 105}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 105}{2}, x = \frac{5 - 105}{2}

a^{2} b^{2} - 36

36 - m^{2}

16 x^{4} + 8 x^{2} + 1

\frac{1 - \frac{a}{a - b}}{\frac{1}{a - b}}

6 x^{2} + 9 x + 3 = 0

What are the solutions to the equation x^2-5x-20=0 ?
The solutions to the equation x^2-5x-20=0 are x=(5+sqrt(105))/2 ,x=(5-sqrt(105))/2
Find the zeros of x^2-5x-20=0
The zeros of x^2-5x-20=0 are x=(5+sqrt(105))/2 ,x=(5-sqrt(105))/2