What are the solutions to the equation -3(x-1)^2+5=-x+4 ?

The solutions to the equation -3(x-1)^2+5=-x+4 are x= 1/3 ,x=2

Find the zeros of -3(x-1)^2+5=-x+4

The zeros of -3(x-1)^2+5=-x+4 are x= 1/3 ,x=2

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- 3 (x - 1)^{2} + 5 = - x + 4

x = \frac{1}{3}, x = 2

Decimal Notation

x = 0.33333 \dots, x = 2

Solution steps

- 3 (x - 1)^{2} + 5 = - x + 4

Expand

- 3 (x - 1)^{2} + 5 : - 3 x^{2} + 6 x + 2

- 3 x^{2} + 6 x + 2 = - x + 4

Move

4

to the left side

- 3 x^{2} + 6 x - 2 = - x

Move

x

to the left side

- 3 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

7^{2} - 4 (- 3) (- 2) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 3 )}, x_{2} = \frac{- 7 - 5}{2 ( - 3 )}

x = \frac{- 7 + 5}{2 ( - 3 )} : \frac{1}{3}

x = \frac{- 7 - 5}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = 2

8 + 2 x = 30

6 x^{2} - 5 x y - 6 y^{2}

(\frac{- 2 x ^{2}}{4 y ^{4}})^{- 3}

x^{2} + 3 x = 54

4 r^{2} - 12 r + 9 = 0

What are the solutions to the equation -3(x-1)^2+5=-x+4 ?
The solutions to the equation -3(x-1)^2+5=-x+4 are x= 1/3 ,x=2
Find the zeros of -3(x-1)^2+5=-x+4
The zeros of -3(x-1)^2+5=-x+4 are x= 1/3 ,x=2