What are the solutions to the equation 8x^2+16x+8=0 ?

The solutions to the equation 8x^2+16x+8=0 are x=-1

Find the zeros of 8x^2+16x+8=0

The zeros of 8x^2+16x+8=0 are x=-1

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8 x^{2} + 16 x + 8 = 0

x = - 1

Solution steps

8 x^{2} + 16 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 \cdot 8}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 \cdot 8 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 8}

x = \frac{- 16}{2 \cdot 8}

\frac{- 16}{2 \cdot 8} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

\frac{( x - 9 ) ( x + 1 )}{x - 2} \geq 0

2 (\frac{7}{25})^{2} - 1

(- 8 k + 1) (- 8 k + 1)

2 t^{2} + 11 t + 5

x - 9 > - 6

What are the solutions to the equation 8x^2+16x+8=0 ?
The solutions to the equation 8x^2+16x+8=0 are x=-1
Find the zeros of 8x^2+16x+8=0
The zeros of 8x^2+16x+8=0 are x=-1