What is (2x+3)(3x-1)<= (6x+1)(x-2) ?

The solution to (2x+3)(3x-1)<= (6x+1)(x-2) is x<= 1/18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2x+3)(3x-1)<= (6x+1)(x-2)

(2 x + 3) (3 x - 1) \leq (6 x + 1) (x - 2)

x \leq \frac{1}{18}

Interval Notation

(- \infty, \frac{1}{18}]

Decimal Notation

x \leq 0.05555 \dots

Solution steps

(2 x + 3) (3 x - 1) \leq (6 x + 1) (x - 2)

Rewrite in standard form

18 x - 1 \leq 0

Move

1

to the right side

18 x \leq 1

Divide both sides by

18

x \leq \frac{1}{18}

x - \frac{1}{2} \geq 1

4 \cdot 7

\frac{1}{ln ( 2 )} ln ∣ 2^{x} + 9 ∣ > 0.999

1 - (- \frac{13}{85})^{2}

2 x^{2} + 15 x + 28

What is (2x+3)(3x-1)<= (6x+1)(x-2) ?
The solution to (2x+3)(3x-1)<= (6x+1)(x-2) is x<= 1/18