What are the solutions to the equation p^2+3p-18=0 ?

The solutions to the equation p^2+3p-18=0 are p=3,p=-6

Find the zeros of p^2+3p-18=0

The zeros of p^2+3p-18=0 are p=3,p=-6

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p^{2} + 3 p - 18 = 0

p = 3, p = - 6

Solution steps

p^{2} + 3 p - 18 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

p_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 3 + 9}{2 \cdot 1}, p_{2} = \frac{- 3 - 9}{2 \cdot 1}

p = \frac{- 3 + 9}{2 \cdot 1} : 3

p = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

p = 3, p = - 6

(3 x^{2} y^{3})^{4}

i^{- 41}

x^{5} + 3 x^{4} - 5 x^{3} - 15 x^{2} + 4 x + 12 > 0

(\frac{3 s}{7 s ^{3}})^{2}

- 3 x + 6 \leq 9

What are the solutions to the equation p^2+3p-18=0 ?
The solutions to the equation p^2+3p-18=0 are p=3,p=-6
Find the zeros of p^2+3p-18=0
The zeros of p^2+3p-18=0 are p=3,p=-6