What is x^5+3x^4-5x^3-15x^2+4x+12>0 ?

The solution to x^5+3x^4-5x^3-15x^2+4x+12>0 is -3 2

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x^5+3x^4-5x^3-15x^2+4x+12>0

x^{5} + 3 x^{4} - 5 x^{3} - 15 x^{2} + 4 x + 12 > 0

- 3 < x < - 2 or - 1 < x < 1 or x > 2

Interval Notation

(- 3, - 2) \cup (- 1, 1) \cup (2, \infty)

Solution steps

x^{5} + 3 x^{4} - 5 x^{3} - 15 x^{2} + 4 x + 12 > 0

Factor

x^{5} + 3 x^{4} - 5 x^{3} - 15 x^{2} + 4 x + 12 : (x + 1) (x - 1) (x + 3) (x + 2) (x - 2)

(x + 1) (x - 1) (x + 3) (x + 2) (x - 2) > 0

Identify the intervals

- 3 < x < - 2 or - 1 < x < 1 or x > 2

(\frac{3 s}{7 s ^{3}})^{2}

- 3 x + 6 \leq 9

3 x^{2} - 6 x + 1 = 0

9 x^{2} + 6 x - 4 = 0

\frac{d ^{2} e ^{3} f ^{5}}{e ^{6} f ^{7} g ^{8}}

What is x^5+3x^4-5x^3-15x^2+4x+12>0 ?
The solution to x^5+3x^4-5x^3-15x^2+4x+12>0 is -3<x<-2\lor-1<x<1\lor x>2