What are the solutions to the equation 3x^2-6x+1=0 ?

The solutions to the equation 3x^2-6x+1=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3

Find the zeros of 3x^2-6x+1=0

The zeros of 3x^2-6x+1=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3

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3 x^{2} - 6 x + 1 = 0

x = \frac{3 + 6}{3}, x = \frac{3 - 6}{3}

Decimal Notation

x = 1.81649 \dots, x = 0.18350 \dots

Solution steps

3 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 1 = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 2 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 6}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 6}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 6}{2 \cdot 3} : \frac{3 + 6}{3}

x = \frac{- ( - 6 ) - 2 6}{2 \cdot 3} : \frac{3 - 6}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 6}{3}, x = \frac{3 - 6}{3}

9 x^{2} + 6 x - 4 = 0

\frac{d ^{2} e ^{3} f ^{5}}{e ^{6} f ^{7} g ^{8}}

2 x^{2} = 10 x + 3

(\frac{a + b}{a - b})^{2}

7 x^{2} = - 28 x

What are the solutions to the equation 3x^2-6x+1=0 ?
The solutions to the equation 3x^2-6x+1=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3
Find the zeros of 3x^2-6x+1=0
The zeros of 3x^2-6x+1=0 are x=(3+sqrt(6))/3 ,x=(3-sqrt(6))/3