What are the solutions to the equation 3x^2-4=-6 ?

The solutions to the equation 3x^2-4=-6 are x=sqrt(2/3)i,x=-sqrt(2/3)i

Find the zeros of 3x^2-4=-6

The zeros of 3x^2-4=-6 are x=sqrt(2/3)i,x=-sqrt(2/3)i

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3 x^{2} - 4 = - 6

x = \frac{2}{3} i, x = - \frac{2}{3} i

Solution steps

3 x^{2} - 4 = - 6

Move

4

to the right side

3 x^{2} = - 2

Divide both sides by

3

x^{2} = - \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{2}{3}, x = - - \frac{2}{3}

- \frac{2}{3} = \frac{2}{3} i

- - \frac{2}{3} = - \frac{2}{3} i

x = \frac{2}{3} i, x = - \frac{2}{3} i

64 a^{3} - 125 b^{3}

(1.2 + x) = 0.32967033 (3.55 - x) (1.4 - x)

- 20 v = 4 v^{2} + 25

1 \geq 2 x^{2} + x

What are the solutions to the equation 3x^2-4=-6 ?
The solutions to the equation 3x^2-4=-6 are x=sqrt(2/3)i,x=-sqrt(2/3)i
Find the zeros of 3x^2-4=-6
The zeros of 3x^2-4=-6 are x=sqrt(2/3)i,x=-sqrt(2/3)i