What are the solutions to the equation x^2-14x+51=0 ?

The solutions to the equation x^2-14x+51=0 are x=7+sqrt(2)i,x=7-sqrt(2)i

Find the zeros of x^2-14x+51=0

The zeros of x^2-14x+51=0 are x=7+sqrt(2)i,x=7-sqrt(2)i

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x^{2} - 14 x + 51 = 0

x = 7 + 2 i, x = 7 - 2 i

Solution steps

x^{2} - 14 x + 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 51}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 51 : 22 i

x_{1, 2} = \frac{- ( - 14 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 2 i}{2 \cdot 1} : 7 + 2 i

x = \frac{- ( - 14 ) - 2 2 i}{2 \cdot 1} : 7 - 2 i

The solutions to the quadratic equation are:

x = 7 + 2 i, x = 7 - 2 i

- 3 x^{2} + 2 x + 8

x^{2} + 3 x - 12 > 0

64 c z^{3} + 27 c x^{3}

- x^{2} = 4

(\frac{3}{2})^{- 5}

What are the solutions to the equation x^2-14x+51=0 ?
The solutions to the equation x^2-14x+51=0 are x=7+sqrt(2)i,x=7-sqrt(2)i
Find the zeros of x^2-14x+51=0
The zeros of x^2-14x+51=0 are x=7+sqrt(2)i,x=7-sqrt(2)i