The solution to x^2-6x-7>4 is x 2sqrt(5)+3

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x^2-6x-7>4

Solution

x^{2} - 6 x - 7 > 4

x < - 25 + 3 or x > 25 + 3

Interval Notation

(- \infty, - 25 + 3) \cup (25 + 3, \infty)

Decimal Notation

x < - 1.47213 \dots or x > 7.47213 \dots

Solution steps

x^{2} - 6 x - 7 > 4

Rewrite in standard form

x^{2} - 6 x - 11 > 0

Complete the square

x^{2} - 6 x - 11 : (x - 3)^{2} - 20

(x - 3)^{2} - 20 > 0

Move

20

to the right side

(x - 3)^{2} > 20

For

u^{n} > a

, if

n

is even then

x - 3 < - 20 or x - 3 > 20

x - 3 < - 20 : x < - 25 + 3

x - 3 > 20 : x > 25 + 3

Combine the intervals

x < - 25 + 3 or x > 25 + 3

\frac{( 1 + i ) ^{2}}{1 - i}

7 x = 78

\frac{2}{3} \cdot \frac{5}{2}

a^{2} b^{2} - 100

\frac{3}{2 6}

What is x^2-6x-7>4 ?
The solution to x^2-6x-7>4 is x<-2sqrt(5)+3\lor x>2sqrt(5)+3