What are the solutions to the equation 2x^2+18=12x ?

The solutions to the equation 2x^2+18=12x are x=3

Find the zeros of 2x^2+18=12x

The zeros of 2x^2+18=12x are x=3

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2 x^{2} + 18 = 12 x

x = 3

Solution steps

2 x^{2} + 18 = 12 x

Move

12 x

to the left side

2 x^{2} + 18 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 12 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 18}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 18 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 2}

x = \frac{- ( - 12 )}{2 \cdot 2}

\frac{- ( - 12 )}{2 \cdot 2} = 3

x = 3

The solution to the quadratic equation is:

x = 3

p^{2} + p - 72

1.1 2^{10}

19 = - 0.1 x^{2} + 70 x

- 19 \leq 4 x + 5 \leq - 3

2 x^{2} + 13 x + 21

What are the solutions to the equation 2x^2+18=12x ?
The solutions to the equation 2x^2+18=12x are x=3
Find the zeros of 2x^2+18=12x
The zeros of 2x^2+18=12x are x=3