What are the solutions to the equation 19=-0.1x^2+70x ?

The solutions to the equation 19=-0.1x^2+70x are x=350-9sqrt(1510),x=350+9sqrt(1510)

Find the zeros of 19=-0.1x^2+70x

The zeros of 19=-0.1x^2+70x are x=350-9sqrt(1510),x=350+9sqrt(1510)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

19 = - 0.1 x^{2} + 70 x

x = 350 - 91510, x = 350 + 91510

Decimal Notation

x = 0.27153 \dots, x = 699.72846 \dots

Solution steps

19 = - 0.1 x^{2} + 70 x

Multiply both sides by

10

190 = - x^{2} + 700 x

Switch sides

- x^{2} + 700 x = 190

Move

190

to the left side

- x^{2} + 700 x - 190 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 700 \pm 70 0 ^{2} - 4 ( - 1 ) ( - 190 )}{2 ( - 1 )}

70 0^{2} - 4 (- 1) (- 190) = 181510

x_{1, 2} = \frac{- 700 \pm 18 1510}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 700 + 18 1510}{2 ( - 1 )}, x_{2} = \frac{- 700 - 18 1510}{2 ( - 1 )}

x = \frac{- 700 + 18 1510}{2 ( - 1 )} : 350 - 91510

x = \frac{- 700 - 18 1510}{2 ( - 1 )} : 350 + 91510

The solutions to the quadratic equation are:

x = 350 - 91510, x = 350 + 91510

- 19 \leq 4 x + 5 \leq - 3

2 x^{2} + 13 x + 21

3 x + 2 < 5 x - 8

x^{\frac{4}{3}} \cdot x^{\frac{2}{5}}

- 2 v (v + 1) = 0

What are the solutions to the equation 19=-0.1x^2+70x ?
The solutions to the equation 19=-0.1x^2+70x are x=350-9sqrt(1510),x=350+9sqrt(1510)
Find the zeros of 19=-0.1x^2+70x
The zeros of 19=-0.1x^2+70x are x=350-9sqrt(1510),x=350+9sqrt(1510)