What is (4x^{-2}y^4)^{-1/2} ?

The solution to (4x^{-2}y^4)^{-1/2} is x/(2y^2)

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simplify (4x^{-2}y^4)^{-1/2}

simplify

(4 x^{- 2} y^{4})^{- \frac{1}{2}}

\frac{x}{2 y ^{2}}

Solution steps

(4 x^{- 2} y^{4})^{- \frac{1}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(4 x^{- 2} y^{4})^{- \frac{1}{2}} = \frac{1}{( 4 x ^{- 2} y ^{4} ) ^{\frac{1}{2}}}

= \frac{1}{( 4 x ^{- 2} y ^{4} ) ^{\frac{1}{2}}}

Simplify

(4 x^{- 2} y^{4})^{\frac{1}{2}} : \frac{2 y ^{2}}{x}

= \frac{1}{\frac{2 y ^{2}}{x}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x}{2 y ^{2}}

297

\frac{25 !}{7 ! ( 25 - 7 ) !}

3 a^{2} - 18 a + 27

4 x^{2} + x - 5 = 0

(15625 x)^{\frac{1}{6}}