What are the solutions to the equation 1^2+1^2=c^2 ?

The solutions to the equation 1^2+1^2=c^2 are c=sqrt(2),c=-sqrt(2)

Find the zeros of 1^2+1^2=c^2

The zeros of 1^2+1^2=c^2 are c=sqrt(2),c=-sqrt(2)

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1^{2} + 1^{2} = c^{2}

c = 2, c = - 2

Decimal Notation

c = 1.41421 \dots, c = - 1.41421 \dots

Solution steps

1^{2} + 1^{2} = c^{2}

Switch sides

c^{2} = 1^{2} + 1^{2}

Simplify

1^{2} + 1^{2} : 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 2, c = - 2

x^{2} - 8 x = - 24

8 x - 2 = - 9 + 7 x

2 x^{2} - 3 = - 3

13.6 \cdot 0.64 + 1.28 \cdot 7.2 + 7.2 \cdot 0.72 + 0.36 \cdot 13.6

5 x - (x - 2) \geq 2 x - 4 (x - 8)

What are the solutions to the equation 1^2+1^2=c^2 ?
The solutions to the equation 1^2+1^2=c^2 are c=sqrt(2),c=-sqrt(2)
Find the zeros of 1^2+1^2=c^2
The zeros of 1^2+1^2=c^2 are c=sqrt(2),c=-sqrt(2)