What are the solutions to the equation (5x+7)^2+10=17 ?

The solutions to the equation (5x+7)^2+10=17 are x=(sqrt(7)-7)/5 ,x=(-sqrt(7)-7)/5

Find the zeros of (5x+7)^2+10=17

The zeros of (5x+7)^2+10=17 are x=(sqrt(7)-7)/5 ,x=(-sqrt(7)-7)/5

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(5 x + 7)^{2} + 10 = 17

x = \frac{7 - 7}{5}, x = \frac{- 7 - 7}{5}

Decimal Notation

x = - 0.87084 \dots, x = - 1.92915 \dots

Solution steps

(5 x + 7)^{2} + 10 = 17

Move

10

to the right side

(5 x + 7)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 7 = 7 : x = \frac{7 - 7}{5}

Solve

5 x + 7 = - 7 : x = \frac{- 7 - 7}{5}

The solutions to the quadratic equation are:

x = \frac{7 - 7}{5}, x = \frac{- 7 - 7}{5}

\frac{3}{5} (- 5) + 21

1407.812857 = 88.29 t + 14.5539

4 x^{2} - 32 x = - 28

- 5 \cdot 0

- 15 r = 102

What are the solutions to the equation (5x+7)^2+10=17 ?
The solutions to the equation (5x+7)^2+10=17 are x=(sqrt(7)-7)/5 ,x=(-sqrt(7)-7)/5
Find the zeros of (5x+7)^2+10=17
The zeros of (5x+7)^2+10=17 are x=(sqrt(7)-7)/5 ,x=(-sqrt(7)-7)/5