What are the solutions to the equation x^2=6x+160 ?

The solutions to the equation x^2=6x+160 are x=16,x=-10

Find the zeros of x^2=6x+160

The zeros of x^2=6x+160 are x=16,x=-10

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x^{2} = 6 x + 160

x = 16, x = - 10

Solution steps

x^{2} = 6 x + 160

Move

160

to the left side

x^{2} - 160 = 6 x

Move

6 x

to the left side

x^{2} - 160 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x - 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 160 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 160) = 26

x_{1, 2} = \frac{- ( - 6 ) \pm 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 26}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 26}{2 \cdot 1}

x = \frac{- ( - 6 ) + 26}{2 \cdot 1} : 16

x = \frac{- ( - 6 ) - 26}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 16, x = - 10

- 2 x + 5 < 7

\frac{( x + 1 )}{x - 2} > 2

x^{2} + 14 x + 1 = 0

3 x^{2} + 8 x - 16 = 0

x + 2 < 2 x - 3 \leq x + 1

What are the solutions to the equation x^2=6x+160 ?
The solutions to the equation x^2=6x+160 are x=16,x=-10
Find the zeros of x^2=6x+160
The zeros of x^2=6x+160 are x=16,x=-10