What is the answer to x^2=(x+3)(x-3)+9 ?

The answer to x^2=(x+3)(x-3)+9 is True for all x

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x^2=(x+3)(x-3)+9

x^{2} = (x + 3) (x - 3) + 9

True for all x

Solution steps

x^{2} = (x + 3) (x - 3) + 9

Expand

(x + 3) (x - 3) + 9 : x^{2}

x^{2} = x^{2}

Move

x^{2}

to the left side

0 = 0

Both sides are equal

True for all x

\frac{2 x ^{2} + 8 y}{6 y ^{3} + 4 x ^{2}}

x^{2} + 6 x - 13 = 0

x^{2} - 18 x + 32

(7 - x)^{2} - 9

4 w^{2} - 28 w = 0

What is the answer to x^2=(x+3)(x-3)+9 ?
The answer to x^2=(x+3)(x-3)+9 is True for all x
Solve for x: x^2=(x+3)(x-3)+9
The solution is True for all x