What are the solutions to the equation ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0 ?

The solutions to the equation ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0 are x=-5,x=1

Find the zeros of ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0

The zeros of ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0 are x=-5,x=1

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\frac{( 2 x ^{(2)} - 7 x ^{(2)} - 20 x + 25 )}{( 2 )} = 0

x = - 5, x = 1

Solution steps

\frac{( 2 x ^{(2)} - 7 x ^{(2)} - 20 x + 25 )}{( 2 )} = 0

Simplify

(2) : 2

\frac{( 2 x ^{(2)} - 7 x ^{(2)} - 20 x + 25 )}{2} = 0

Multiply both sides by

2

- 5 x^{2} - 20 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 5 ) \cdot 25}{2 ( - 5 )}

(- 20)^{2} - 4 (- 5) \cdot 25 = 30

x_{1, 2} = \frac{- ( - 20 ) \pm 30}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 30}{2 ( - 5 )}, x_{2} = \frac{- ( - 20 ) - 30}{2 ( - 5 )}

x = \frac{- ( - 20 ) + 30}{2 ( - 5 )} : - 5

x = \frac{- ( - 20 ) - 30}{2 ( - 5 )} : 1

The solutions to the quadratic equation are:

x = - 5, x = 1

70 = - 16 t^{2} + 70 t + 5

\frac{a - b}{( b - a ) ^{2}}

v^{2} + 2 v + 1 = 0

10 u^{2} + 17 u + 3 = 0

\frac{7}{4} - \frac{2}{3}

What are the solutions to the equation ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0 ?
The solutions to the equation ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0 are x=-5,x=1
Find the zeros of ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0
The zeros of ((2x^{(2)}-7x^{(2)}-20x+25))/((2))=0 are x=-5,x=1