What is (6-6i)/(-sqrt(3)+i) ?

The solution to (6-6i)/(-sqrt(3)+i) is -(3(sqrt(3)+1))/2+(3(-1+sqrt(3)))/2 i

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simplify (6-6i)/(-sqrt(3)+i)

simplify

\frac{6 - 6 i}{- 3 + i}

- \frac{3 ( 3 + 1 )}{2} + \frac{3 ( - 1 + 3 )}{2} i

Solution steps

\frac{6 - 6 i}{- 3 + i}

Multiply by the conjugate

\frac{- 3 - i}{- 3 - i}

= \frac{( 6 - 6 i ) ( - 3 - i )}{( - 3 + i ) ( - 3 - i )}

Simplify

\frac{( 6 - 6 i ) ( - 3 - i )}{( - 3 + i ) ( - 3 - i )} : \frac{- 6 3 - 6 + 6 i ( - 1 + 3 )}{4}

= \frac{- 6 3 - 6 + 6 i ( - 1 + 3 )}{4}

Rewrite in standard complex form:

- \frac{3 ( 3 + 1 )}{2} + \frac{3 ( - 1 + 3 )}{2} i

= - \frac{3 ( 3 + 1 )}{2} + \frac{3 ( - 1 + 3 )}{2} i

\frac{4}{3 + 2}

\frac{5}{9 i}

- (\frac{1}{3}) x^{2} + 2 x + 4 = 0

(\frac{1}{6})^{6}

8 z^{2} - 2 z - 3 = 0

What is (6-6i)/(-sqrt(3)+i) ?
The solution to (6-6i)/(-sqrt(3)+i) is -(3(sqrt(3)+1))/2+(3(-1+sqrt(3)))/2 i