What are the solutions to the equation 4r^2+44r+121=0 ?

The solutions to the equation 4r^2+44r+121=0 are r=-11/2

Find the zeros of 4r^2+44r+121=0

The zeros of 4r^2+44r+121=0 are r=-11/2

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4 r^{2} + 44 r + 121 = 0

r = - \frac{11}{2}

Solution steps

4 r^{2} + 44 r + 121 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 44 \pm 4 4 ^{2} - 4 \cdot 4 \cdot 121}{2 \cdot 4}

4 4^{2} - 4 \cdot 4 \cdot 121 = 0

r_{1, 2} = \frac{- 44 \pm 0}{2 \cdot 4}

r = \frac{- 44}{2 \cdot 4}

\frac{- 44}{2 \cdot 4} = - \frac{11}{2}

r = - \frac{11}{2}

The solution to the quadratic equation is:

r = - \frac{11}{2}

9 (x + 2)^{2} - 4 = 2

- 12 (x - 8) = 3 (x + 17)

125 - 300 n + 240 n^{2} - 64 n^{3}

30 a^{2} - 57 a - 45

- 3 < 1 - 2 n \leq 4

What are the solutions to the equation 4r^2+44r+121=0 ?
The solutions to the equation 4r^2+44r+121=0 are r=-11/2
Find the zeros of 4r^2+44r+121=0
The zeros of 4r^2+44r+121=0 are r=-11/2