What are the solutions to the equation 2+4x^2=1 ?

The solutions to the equation 2+4x^2=1 are x= 1/2 i,x=-1/2 i

Find the zeros of 2+4x^2=1

The zeros of 2+4x^2=1 are x= 1/2 i,x=-1/2 i

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2 + 4 x^{2} = 1

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

2 + 4 x^{2} = 1

Move

2

to the right side

4 x^{2} = - 1

Divide both sides by

4

x^{2} = - \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{4}, x = - - \frac{1}{4}

- \frac{1}{4} = \frac{1}{2} i

- - \frac{1}{4} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

\frac{8}{5} - \frac{3}{2}

x^{2} = 8.33 \cdot 1 0^{- 4} (0.5 - x)

0 = x^{2} + 5 x - 6

2 r = - 17

24 s^{2} - s - 3 = 0

What are the solutions to the equation 2+4x^2=1 ?
The solutions to the equation 2+4x^2=1 are x= 1/2 i,x=-1/2 i
Find the zeros of 2+4x^2=1
The zeros of 2+4x^2=1 are x= 1/2 i,x=-1/2 i