What are the solutions to the equation 4y^2-25=0 ?

The solutions to the equation 4y^2-25=0 are y= 5/2 ,y=-5/2

Find the zeros of 4y^2-25=0

The zeros of 4y^2-25=0 are y= 5/2 ,y=-5/2

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4 y^{2} - 25 = 0

y = \frac{5}{2}, y = - \frac{5}{2}

Solution steps

4 y^{2} - 25 = 0

Move

25

to the right side

4 y^{2} = 25

Divide both sides by

4

y^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{25}{4}, y = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

y = \frac{5}{2}, y = - \frac{5}{2}

2 h^{2} + 9 h + 7

u^{2} - 27 u + 50 = 0

4^{2} + 4 2^{2} = 4 3^{2}

- 4 \leq x - 7 \leq 4

x^{2} - 18 x + 69 = 0

What are the solutions to the equation 4y^2-25=0 ?
The solutions to the equation 4y^2-25=0 are y= 5/2 ,y=-5/2
Find the zeros of 4y^2-25=0
The zeros of 4y^2-25=0 are y= 5/2 ,y=-5/2