What are the solutions to the equation 12x^2-96x+144=0 ?

The solutions to the equation 12x^2-96x+144=0 are x=6,x=2

Find the zeros of 12x^2-96x+144=0

The zeros of 12x^2-96x+144=0 are x=6,x=2

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12 x^{2} - 96 x + 144 = 0

x = 6, x = 2

Solution steps

12 x^{2} - 96 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 12 \cdot 144}{2 \cdot 12}

(- 96)^{2} - 4 \cdot 12 \cdot 144 = 48

x_{1, 2} = \frac{- ( - 96 ) \pm 48}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 48}{2 \cdot 12}, x_{2} = \frac{- ( - 96 ) - 48}{2 \cdot 12}

x = \frac{- ( - 96 ) + 48}{2 \cdot 12} : 6

x = \frac{- ( - 96 ) - 48}{2 \cdot 12} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

6 y^{2} + 11 y - 21

\frac{86 + 85 + 93 + 95 + x}{5} \geq 90

- 60 x + 32 = - 60 x + 60

v^{2} - 5 v - 6 = 0

15 x^{2} + 17 = 15 (x + 1)^{2}

What are the solutions to the equation 12x^2-96x+144=0 ?
The solutions to the equation 12x^2-96x+144=0 are x=6,x=2
Find the zeros of 12x^2-96x+144=0
The zeros of 12x^2-96x+144=0 are x=6,x=2