What are the solutions to the equation v^2-5v-6=0 ?

The solutions to the equation v^2-5v-6=0 are v=6,v=-1

Find the zeros of v^2-5v-6=0

The zeros of v^2-5v-6=0 are v=6,v=-1

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v^{2} - 5 v - 6 = 0

v = 6, v = - 1

Solution steps

v^{2} - 5 v - 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 6) = 7

v_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 1}, v_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 1}

v = \frac{- ( - 5 ) + 7}{2 \cdot 1} : 6

v = \frac{- ( - 5 ) - 7}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

v = 6, v = - 1

15 x^{2} + 17 = 15 (x + 1)^{2}

4 z^{2} + z + 4 = 0

y + 4 = y - 4

\frac{4}{11} n = - \frac{16}{55}

- 2 + 2 x \geq (\frac{( x + 3 )}{2}) \geq - 10

What are the solutions to the equation v^2-5v-6=0 ?
The solutions to the equation v^2-5v-6=0 are v=6,v=-1
Find the zeros of v^2-5v-6=0
The zeros of v^2-5v-6=0 are v=6,v=-1