What are the solutions to the equation 4x^2=2x+6 ?

The solutions to the equation 4x^2=2x+6 are x= 3/2 ,x=-1

Find the zeros of 4x^2=2x+6

The zeros of 4x^2=2x+6 are x= 3/2 ,x=-1

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4 x^{2} = 2 x + 6

x = \frac{3}{2}, x = - 1

Decimal Notation

x = 1.5, x = - 1

Solution steps

4 x^{2} = 2 x + 6

Move

6

to the left side

4 x^{2} - 6 = 2 x

Move

2 x

to the left side

4 x^{2} - 6 - 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 2 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 (- 6) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 4}

x = \frac{- ( - 2 ) + 10}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 2 ) - 10}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

∣ x + 2 ∣ + 6 \leq 11

(\frac{5}{6}) (\frac{2}{3})

12 x^{2} + 50 x + 50

- 8 x - 3 x = - 11 x

- 5 + 11 x - 2 x^{2} = 0

What are the solutions to the equation 4x^2=2x+6 ?
The solutions to the equation 4x^2=2x+6 are x= 3/2 ,x=-1
Find the zeros of 4x^2=2x+6
The zeros of 4x^2=2x+6 are x= 3/2 ,x=-1