What are the solutions to the equation 1/2 x^2+5x=-14 ?

The solutions to the equation 1/2 x^2+5x=-14 are x=-5+sqrt(3)i,x=-5-sqrt(3)i

Find the zeros of 1/2 x^2+5x=-14

The zeros of 1/2 x^2+5x=-14 are x=-5+sqrt(3)i,x=-5-sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{2} x^{2} + 5 x = - 14

x = - 5 + 3 i, x = - 5 - 3 i

Solution steps

\frac{1}{2} x^{2} + 5 x = - 14

Multiply both sides by

2

x^{2} + 10 x = - 28

Move

28

to the left side

x^{2} + 10 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 28 : 23 i

x_{1, 2} = \frac{- 10 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 3 i}{2 \cdot 1}

x = \frac{- 10 + 2 3 i}{2 \cdot 1} : - 5 + 3 i

x = \frac{- 10 - 2 3 i}{2 \cdot 1} : - 5 - 3 i

The solutions to the quadratic equation are:

x = - 5 + 3 i, x = - 5 - 3 i

x^{2} + 5 x + 7 = 0

x^{8} - 29 x^{4} + 100

(\frac{2 ^{2} + 3 ^{2} + 3 ^{3}}{9})^{2} \cdot (\frac{1}{3})^{- 5}

26 = 2 π r

(2 - 3 i) (5 + i)

What are the solutions to the equation 1/2 x^2+5x=-14 ?
The solutions to the equation 1/2 x^2+5x=-14 are x=-5+sqrt(3)i,x=-5-sqrt(3)i
Find the zeros of 1/2 x^2+5x=-14
The zeros of 1/2 x^2+5x=-14 are x=-5+sqrt(3)i,x=-5-sqrt(3)i