What are the solutions to the equation 2x^2+2x-1=0 ?

The solutions to the equation 2x^2+2x-1=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

Find the zeros of 2x^2+2x-1=0

The zeros of 2x^2+2x-1=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

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2 x^{2} + 2 x - 1 = 0

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

Solution steps

2 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 1) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 2}

x = \frac{- 2 + 2 3}{2 \cdot 2} : \frac{- 1 + 3}{2}

x = \frac{- 2 - 2 3}{2 \cdot 2} : - \frac{1 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

\frac{1}{2} (1)^{2}

5 x + 12 \leq 3 x - 16

\frac{s}{6} = - 3

6 x - 6 \leq - 30

(x + 1) (x - 1) = 0

What are the solutions to the equation 2x^2+2x-1=0 ?
The solutions to the equation 2x^2+2x-1=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2
Find the zeros of 2x^2+2x-1=0
The zeros of 2x^2+2x-1=0 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2