What are the solutions to the equation 952=16t^2 ?

The solutions to the equation 952=16t^2 are t=sqrt(119/2),t=-sqrt(119/2)

Find the zeros of 952=16t^2

The zeros of 952=16t^2 are t=sqrt(119/2),t=-sqrt(119/2)

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952 = 16 t^{2}

t = \frac{119}{2}, t = - \frac{119}{2}

Decimal Notation

t = 7.71362 \dots, t = - 7.71362 \dots

Solution steps

952 = 16 t^{2}

Switch sides

16 t^{2} = 952

Divide both sides by

16

t^{2} = \frac{119}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{119}{2}, t = - \frac{119}{2}

2 t > 8

3 x^{2} + 13 x = 10

\frac{1}{7} x^{2} + \frac{1}{21} x - 1 = 0

\frac{7 π}{6} + 2 π

\frac{3}{4} \cdot \frac{2}{3}

What are the solutions to the equation 952=16t^2 ?
The solutions to the equation 952=16t^2 are t=sqrt(119/2),t=-sqrt(119/2)
Find the zeros of 952=16t^2
The zeros of 952=16t^2 are t=sqrt(119/2),t=-sqrt(119/2)