What are the solutions to the equation 3m^2+10m-36=-4 ?

The solutions to the equation 3m^2+10m-36=-4 are m=2,m=-16/3

Find the zeros of 3m^2+10m-36=-4

The zeros of 3m^2+10m-36=-4 are m=2,m=-16/3

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3 m^{2} + 10 m - 36 = - 4

m = 2, m = - \frac{16}{3}

Solution steps

3 m^{2} + 10 m - 36 = - 4

Move

4

to the left side

3 m^{2} + 10 m - 32 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 32 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 32) = 22

m_{1, 2} = \frac{- 10 \pm 22}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 10 + 22}{2 \cdot 3}, m_{2} = \frac{- 10 - 22}{2 \cdot 3}

m = \frac{- 10 + 22}{2 \cdot 3} : 2

m = \frac{- 10 - 22}{2 \cdot 3} : - \frac{16}{3}

The solutions to the quadratic equation are:

m = 2, m = - \frac{16}{3}

∣ 2 x - 3 ∣ \geq 5

8 x - 4 > 13 - 3 x

16 = \frac{1}{2} (7 x - 6)

0 = - x^{2} + 16

x^{3} + 3 x^{2} - 10 x - 24

What are the solutions to the equation 3m^2+10m-36=-4 ?
The solutions to the equation 3m^2+10m-36=-4 are m=2,m=-16/3
Find the zeros of 3m^2+10m-36=-4
The zeros of 3m^2+10m-36=-4 are m=2,m=-16/3