What are the solutions to the equation x^2-4x-100=0 ?

The solutions to the equation x^2-4x-100=0 are x=2(1+sqrt(26)),x=2(1-sqrt(26))

Find the zeros of x^2-4x-100=0

The zeros of x^2-4x-100=0 are x=2(1+sqrt(26)),x=2(1-sqrt(26))

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x^{2} - 4 x - 100 = 0

x = 2 (1 + 26), x = 2 (1 - 26)

Solution steps

x^{2} - 4 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 100 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 100) = 426

x_{1, 2} = \frac{- ( - 4 ) \pm 4 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 26}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 26}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 26}{2 \cdot 1} : 2 (1 + 26)

x = \frac{- ( - 4 ) - 4 26}{2 \cdot 1} : 2 (1 - 26)

The solutions to the quadratic equation are:

x = 2 (1 + 26), x = 2 (1 - 26)

20 + 10 a \geq - 20

4 w^{3} - 9 w

7 x + 4 = 39

16 x^{4} - 625 y^{4}

4 x^{2} - 8 = - 20

What are the solutions to the equation x^2-4x-100=0 ?
The solutions to the equation x^2-4x-100=0 are x=2(1+sqrt(26)),x=2(1-sqrt(26))
Find the zeros of x^2-4x-100=0
The zeros of x^2-4x-100=0 are x=2(1+sqrt(26)),x=2(1-sqrt(26))