What are the solutions to the equation 4x^2-8=-20 ?

The solutions to the equation 4x^2-8=-20 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of 4x^2-8=-20

The zeros of 4x^2-8=-20 are x=sqrt(3)i,x=-sqrt(3)i

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4 x^{2} - 8 = - 20

x = 3 i, x = - 3 i

Solution steps

4 x^{2} - 8 = - 20

Move

8

to the right side

4 x^{2} = - 12

Divide both sides by

4

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

- 2 x \leq - 4

- 4 - - 162 - 81 - - 72

- 2 m^{2} + 19 m - 24

2 (x + \frac{3}{4})^{2} - 5 = 123

\frac{4}{3} x - \frac{2}{5} = \frac{7}{5} x - \frac{1}{10}

What are the solutions to the equation 4x^2-8=-20 ?
The solutions to the equation 4x^2-8=-20 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of 4x^2-8=-20
The zeros of 4x^2-8=-20 are x=sqrt(3)i,x=-sqrt(3)i