What are the solutions to the equation (z+4/3)^2=-3 ?

The solutions to the equation (z+4/3)^2=-3 are z=sqrt(3)i-4/3 ,z=-sqrt(3)i-4/3

Find the zeros of (z+4/3)^2=-3

The zeros of (z+4/3)^2=-3 are z=sqrt(3)i-4/3 ,z=-sqrt(3)i-4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(z + \frac{4}{3})^{2} = - 3

z = 3 i - \frac{4}{3}, z = - 3 i - \frac{4}{3}

Solution steps

(z + \frac{4}{3})^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + \frac{4}{3} = - 3 : z = 3 i - \frac{4}{3}

Solve

z + \frac{4}{3} = - - 3 : z = - 3 i - \frac{4}{3}

The solutions to the quadratic equation are:

z = 3 i - \frac{4}{3}, z = - 3 i - \frac{4}{3}

(- 5 x^{4} y^{2})^{2}

∣ x + 1 ∣ \geq 7 - 2 x

\frac{x ^{2} + 5 x - 6}{x ^{2} - 8 x + 16} \geq 0

6 x + 1 \leq 4 x - 9

\frac{1}{4} (8 - 16 x) \leq - 6

What are the solutions to the equation (z+4/3)^2=-3 ?
The solutions to the equation (z+4/3)^2=-3 are z=sqrt(3)i-4/3 ,z=-sqrt(3)i-4/3
Find the zeros of (z+4/3)^2=-3
The zeros of (z+4/3)^2=-3 are z=sqrt(3)i-4/3 ,z=-sqrt(3)i-4/3