What are the solutions to the equation 7y^2-7y=0 ?

The solutions to the equation 7y^2-7y=0 are y=1,y=0

Find the zeros of 7y^2-7y=0

The zeros of 7y^2-7y=0 are y=1,y=0

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7 y^{2} - 7 y = 0

y = 1, y = 0

Solution steps

7 y^{2} - 7 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 7)^{2} - 4 \cdot 7 \cdot 0 = 7

y_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 7}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 7}, y_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 7}

y = \frac{- ( - 7 ) + 7}{2 \cdot 7} : 1

y = \frac{- ( - 7 ) - 7}{2 \cdot 7} : 0

The solutions to the quadratic equation are:

y = 1, y = 0

6 p^{2} - 17 p - 45

a^{5} b^{7} - a^{4} b^{3} + a^{3} b^{8} - a^{3} b^{3}

- \frac{5}{6} x = 10

x^{2} + 8 x = 240

- 5 k + 10 = - 2 k - 14

What are the solutions to the equation 7y^2-7y=0 ?
The solutions to the equation 7y^2-7y=0 are y=1,y=0
Find the zeros of 7y^2-7y=0
The zeros of 7y^2-7y=0 are y=1,y=0