What are the solutions to the equation 4x^2+12x+15=0 ?

The solutions to the equation 4x^2+12x+15=0 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)

Find the zeros of 4x^2+12x+15=0

The zeros of 4x^2+12x+15=0 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)

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4 x^{2} + 12 x + 15 = 0

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

Solution steps

4 x^{2} + 12 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 15}{2 \cdot 4}

Simplify

1 2^{2} - 4 \cdot 4 \cdot 15 : 46 i

x_{1, 2} = \frac{- 12 \pm 4 6 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 4 6 i}{2 \cdot 4}, x_{2} = \frac{- 12 - 4 6 i}{2 \cdot 4}

x = \frac{- 12 + 4 6 i}{2 \cdot 4} : - \frac{3}{2} + i \frac{3}{2}

x = \frac{- 12 - 4 6 i}{2 \cdot 4} : - \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

5 x^{2} + 4 x = 1

\frac{2 + i}{3 + i}

- - 16

4 a^{2} + 6 = 0

3 x - 6 > \frac{1}{2}

What are the solutions to the equation 4x^2+12x+15=0 ?
The solutions to the equation 4x^2+12x+15=0 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)
Find the zeros of 4x^2+12x+15=0
The zeros of 4x^2+12x+15=0 are x=-3/2+isqrt(3/2),x=-3/2-isqrt(3/2)