What are the solutions to the equation 4a^2+6=0 ?

The solutions to the equation 4a^2+6=0 are a=sqrt(3/2)i,a=-sqrt(3/2)i

Find the zeros of 4a^2+6=0

The zeros of 4a^2+6=0 are a=sqrt(3/2)i,a=-sqrt(3/2)i

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4 a^{2} + 6 = 0

a = \frac{3}{2} i, a = - \frac{3}{2} i

Solution steps

4 a^{2} + 6 = 0

Move

6

to the right side

4 a^{2} = - 6

Divide both sides by

4

a^{2} = - \frac{3}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - \frac{3}{2}, a = - - \frac{3}{2}

- \frac{3}{2} = \frac{3}{2} i

- - \frac{3}{2} = - \frac{3}{2} i

a = \frac{3}{2} i, a = - \frac{3}{2} i

3 x - 6 > \frac{1}{2}

2 x^{4} + 4 x^{3} - 30 x^{2}

- x^{2} - 4 x - 4 > 0

\frac{x}{11} - 4 = 7

x^{2} - 39 = - 10 x

What are the solutions to the equation 4a^2+6=0 ?
The solutions to the equation 4a^2+6=0 are a=sqrt(3/2)i,a=-sqrt(3/2)i
Find the zeros of 4a^2+6=0
The zeros of 4a^2+6=0 are a=sqrt(3/2)i,a=-sqrt(3/2)i