What is ((2n)!)/((2(n+1))!) ?

The solution to ((2n)!)/((2(n+1))!) is 1/((2n+1)(2n+2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2n)!)/((2(n+1))!)

simplify

\frac{( 2 n ) !}{( 2 ( n + 1 ) ) !}

\frac{1}{( 2 n + 1 ) ( 2 n + 2 )}

Solution steps

\frac{( 2 n ) !}{( 2 ( n + 1 ) ) !}

Expand

2 (n + 1) : 2 n + 2

= \frac{( 2 n ) !}{( 2 n + 2 ) !}

Cancel the factorials:

\frac{n !}{( n + m ) !} = \frac{1}{( n + 1 ) \cdot ( n + 2 ) \dots ( n + m )}

\frac{( 2 n ) !}{( 2 n + 2 ) !} = \frac{1}{( 2 n + 1 ) ( 2 n + 2 )}

= \frac{1}{( 2 n + 1 ) ( 2 n + 2 )}

(3 6^{\frac{1}{2}})^{5}

6 x - 7 < - 37

2916

\frac{8 ^{- 4}}{4 ^{- 4}}

12 x^{2} - 9 = - 12

What is ((2n)!)/((2(n+1))!) ?
The solution to ((2n)!)/((2(n+1))!) is 1/((2n+1)(2n+2))